10,000 Depositions Later: The Premier Litigation Guide for Superior Deposition Practice

10,000 Depositions Later: The Premier Litigation Guide for Superior Deposition Practice

Matematika 1. Tentukan hasil dari operasi bilangan berpangkat berikut.
[tex] c. \: \frac{( {3}^{2}) {}^{3} . {5}^{ - 2} }{15 {}^{ - 1} } \\ \\ d. \: \ \frac{ {2}^{4}. {5}^{ - 3} . {9}^{2} }{8 \: . \: {3}^{6} . {125}^{ - 1} } [/tex]

1. Tentukan hasil dari operasi bilangan berpangkat berikut.
[tex] c. \: \frac{( {3}^{2}) {}^{3} . {5}^{ - 2} }{15 {}^{ - 1} } \\ \\ d. \: \ \frac{ {2}^{4}. {5}^{ - 3} . {9}^{2} }{8 \: . \: {3}^{6} . {125}^{ - 1} } [/tex]

Penjelasan dengan langkah-langkah:

[tex] \frac{(3 {}^{2}) {}^{3} .5 {}^{ - 2} }{(15) { }^{ - 1} } = \frac{3 {}^{6}.5 {}^{ - 2} }{(3 \times 5) {}^{ -1} } = \frac{3 {}^{6}.5 {}^{ - 2} }{3 {}^{ -1}.5 {}^{ -1} } = 3 {}^{7} .5 {}^{ -1 } = 3 {}^{7} . \frac{1}{5} = \frac{3 {}^{7} }{5} [/tex]

D.

[tex] \frac{2 {}^{4} .5 {}^{ -3}.9 {}^{2} }{8.3 {}^{6}.125 {}^{ - 1} } = \frac{2 {}^{4}.5 {}^{ - 3} .3 {}^{4} }{2 {}^{3}.3 {}^{6} .5 {}^{ - 3} } = 2.3 {}^{ - 2} = 2 \times \frac{1}{9} = \frac{2}{9} [/tex]

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